Question

A particle with charge $5\mu C$ and moving with velocity $2\times {10}^{6}m/s$, enters normally in a magnetic field of 2T. The magnetic force experienced by the particle is

• A. 12 N
• B. 5 N
• C. 20 N
• D. 80 N

Answer 1

The correct option is C 20 N

Charge, $q=5\mu C=5\times {10}^{-6}C$
$Velocity,v=2\times {10}^{6}m/s$
Magnetic filed, B = 2T
Angle between the magnetic field and velocity, $\theta ={90}^{\circ }$,
Magnitude of magnetic force experienced by the charged particle:
$|\overline{F}|=|q\overline{v}\times \overline{B}|=qvBsin{90}^{\circ }$
$=qvB=5\times {10}^{-6}\times 2\times {10}^6\times 2[\because sin{90}^{\circ }=1]=20N$
Hence, the correct answer is option (3).