Question

A particle with charge $2\mu C$, moving with velocity $2\times {10}^{6}m/s$, enters normally in a magnetic field of 4T. The force experienced by the particle is?

• A. 4 N
• B. 8 N
• C. 12 N
• D. 16 N

Answer 1

The correct option is D 16 N

Magnitude of the force experienced by a charge particle in a magnetic field is given by the formula:
$F=qvBsin\theta$
$\theta ={90}^0$
$\Rightarrow F=2\times {10}^{-6}\times 2\times {10}^6\times 4$
$\Rightarrow F=16N$