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Question

A P.D. of 4 V is applied to two resistors of 6 ohms and 2 ohms connected in series. Calculate:

(a) the combined resistance

(b) the current flowing

(c) the p.d. across the 6 ohms resistor


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Solution

Part (a):

Step 1 Given:

  1. Resistance, R1=6Ω
  2. Resistance, R2=2Ω

The combined resistance of the given two resistors:

The combined resistance when connected in series can be calculated by,

Step 2 : formula used,

Req=R1+R2

As resistance is in series connection.

Step 3: Solution

Req=6+2=8Ω.

Hence, the combined resistance of the given two resistors is 8 Ohms.

Part (b):

The current flowing through the circuit:

Step 1 Given

  1. The current flowing I can be calculated using the formula V=IR
  2. P.D applied to two resistors of 6 ohms and 2 ohms, V=4V

Step 2: Formula used

I=VR

Step 3: Solution

I=48I=0.5A

Hence, a current0.5A is flowing through the circuit.

Part (c):

The potential difference across the 6 Ωresistors:

Step 1 Given,

I=0.5A

R=6Ω

Step 2 Formula used

V=IR

Step 3 Solution

V=0.5×6V=3V

Hence, the potential difference across the 6 Ohm resistor is 3 V.


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