Question

# A P.D. of 4 V is applied to two resistors of 6 ohms and 2 ohms connected in series. Calculate:(a) the combined resistance (b) the current flowing (c) the p.d. across the 6 ohms resistor

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Solution

## Part (a):Step 1 Given:Resistance, ${R}_{1}=6\Omega$Resistance, ${R}_{2}=2\Omega$The combined resistance of the given two resistors:The combined resistance when connected in series can be calculated by, Step 2 : formula used,${R}_{eq}={R}_{1}+{R}_{2}$ As resistance is in series connection.Step 3: Solution${R}_{eq}=6+2\phantom{\rule{0ex}{0ex}}=8\Omega .$Hence, the combined resistance of the given two resistors is 8 Ohms.Part (b):The current flowing through the circuit:Step 1 GivenThe current flowing $I$ can be calculated using the formula $V=IR$P.D applied to two resistors of 6 ohms and 2 ohms, $V=4V$Step 2: Formula used$I=\frac{V}{R}$Step 3: Solution$I=\frac{4}{8}\phantom{\rule{0ex}{0ex}}I=0.5A$Hence, a current$0.5A$ is flowing through the circuit.Part (c):The potential difference across the 6 $\Omega$resistors:Step 1 Given, $I=0.5A$$R=6\Omega$Step 2 Formula used$V=IR$Step 3 Solution$V=0.5×6\phantom{\rule{0ex}{0ex}}V=3V$Hence, the potential difference across the 6 Ohm resistor is 3 V.

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