A pebble thrown vertically upwards with an initial velocity $50 m s^{- 1}$ comes to a stop in 5 s. Find the retardation assuming displacement in upwards direction to be positive.

- 10 m s^{- 2}

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10 m s^{- 2}

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250 m s^{- 2}

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- 250 m s^{- 2}

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Solution

The correct option is B $10 m s^{- 2}$
Acceleration $a = \frac{v - u}{t} = \frac{0 - 50 m s^{- 1}}{5 s}$
$= - 10 m s^{- 2}$
$Retardation = - Acceleration$
$= 10 m s^{- 2}$

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