A pendulum clock is taken to the bottom of a deep mine. Will it gain or lose time ? How should its length be altered to correct the time?

looses time, length to be increased

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looses time, length to be decreased

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gains time, length to be increased

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gains time, length to be decreased

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Solution

The correct option is A looses time, length to be decreased
as we go inside mine g decrease , so T
increases , it loses time as T $α \sqrt{l}$
$l$ has to be decreased to regain.

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A simple pendulum of length 40 cm is taken inside a deep mine. Assume for the time being that the mine is 1600 km deep. Calculate the time period of the pendulum there. Radius of the earth = 6400 km.

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A pendulum clock is taken to the bottom of a deep mine. Will it gain or lose time ? How should its length be altered to correct the time?

The correct option is A looses time, length to be decreasedas we go inside mine g decrease , so Tincreases , it loses time as T α√ll has to be decreased to regain.

The correct option is A looses time, length to be decreased
as we go inside mine g decrease , so T
increases , it loses time as T $α \sqrt{l}$
$l$ has to be decreased to regain.