Question

A pendulum clock that keeps correct time on the earth is taken to the moon it will run

• A. At correct rate
• B. 6 time faster
• C. times faster
• D. times slowly

Answer 1

The correct option is C times faster

The time period of a simple pendulum is
$T=2\pi \sqrt{\frac{l}{g}}$ g is lesser on moon
$\Rightarrow Twillbegreater\Rightarrow \frac{T_e}{T_m}=\sqrt{\frac{g_m}{g_e}}=\sqrt{\frac{\frac{g_e}{6}}{g_e}}=\frac{1}{\sqrt{6}}\Rightarrow T_m=\sqrt{6}{T}_e$