Question

A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is $20m/s^2$ at a distance of $5m$ from the moving position. The time period of oscillation is

• A. $2s$
• B. $2\pi s$
• C. $1s$
• D. $\pi s$

Answer 1

The correct option is D $\pi s$

Since in SHM, magnitude of acceleration is given as
$a={\omega }^{2}x$
$20={\omega }^2\times 5$
$\omega =2rad/s$

Now, Time Period
$T=\frac{2\pi }{\omega }$
$=\pi s$