A perfect gas at $27^{0} C$ is heated at constant pressure so as to double its volume. The increase in temperature of the gas will be

300^{0} C

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54^{0} C

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327^{0} C

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600^{0} C

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Solution

The correct option is A $300^{0} C$
$\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}} [P_{1} = P_{2} = P, V_{1} = V, V_{2} = 2 V] \Rightarrow T_{2} = \frac{P_{2} V_{2} T_{1}}{P_{1} V_{1}} = \frac{2 V}{V} \cdot 300 = 600 K = 327 ℃ ∴ T_{2} - T_{1} = 300 ℃$

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