A perpendicular is drawn to a line segment $¯ ¯¯¯¯¯¯¯¯¯ ¯ M N$ at N using protractor and point P is marked on perpendicular , then_______ .

¯ ¯¯¯¯¯¯¯¯ ¯ M P ⊥ ¯ ¯¯¯¯¯¯¯ ¯ N P

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¯ ¯¯¯¯¯¯¯¯¯ ¯ M N ∥ ¯ ¯¯¯¯¯¯¯ ¯ N P

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¯ ¯¯¯¯¯¯¯¯¯ ¯ M N ∥ ¯ ¯¯¯¯¯¯¯¯ ¯ M P

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¯ ¯¯¯¯¯¯¯¯¯ ¯ M N ⊥ ¯ ¯¯¯¯¯¯¯ ¯ N P

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Solution

The correct option is D $¯ ¯¯¯¯¯¯¯¯¯ ¯ M N ⊥ ¯ ¯¯¯¯¯¯¯ ¯ N P$

$\Rightarrow$ In the given figure, $¯ ¯¯¯¯¯¯¯¯¯ ¯ M N$ is a line segment and at point N using protractor and point P we have drawn perpendicular.
$∴$ We can say, $¯ ¯¯¯¯¯¯¯¯¯ ¯ M N ⊥ ¯ ¯¯¯¯¯¯¯ ¯ N P$

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