Question

A person adds 1.71 g of sugar in order to sweeten his tea. The number of C atoms added are (molar mass of sugar =342):

• A. $3.6\times {10}^{22}$
• B. $7.2\times {10}^{21}$
• C. $0.05$
• D. $6.6\times {10}^{22}$

Answer 1

The correct option is A $3.6\times {10}^{22}$

1.71 g of sugar = $\frac{1.71}{342}$ moles = $5\times {10}^{-3}$ mol = $5\times {10}^{-3}\times 6.022\times {10}^{23}\times 12$ --- C atoms = $3.6\times {10}^{22}$ C atoms