Question

Rakesh needs 1.71 g of sugar $\left(C_{12}{H}_{22}{O}_{11}\right)$ to sweeten his tea. What would be the number of carbon atoms present in his tea ?

• A. $3.6\times {10}^{22}$
• B. $7.2\times {10}^1$
• C. $0.05\times {10}^{23}$
• D. $6.6\times {10}^{22}$

Answer 1

The correct option is A $3.6\times {10}^{22}$

1 mole of sugar occupies $N_A$ molecules

1.71 g equals $=\frac{1.71}{342}=0.005$ moles

$12\times 0.005$ mole of carbon occupies $0.005\times 12\times N_A$ aroms

The number of carbon atoms present in his tea would be $3.6\times {10}^{22}$