Question

A person has mass 60 kg. The area under feet of the person is $180c{m}^2$. Find the pressure exerted on the ground by the person. [Take $g=10m{s}^{-2}$].

Answer 1

Step 1: Given data

Mass of a person $=60kg$

Area under feet of the person is $180c{m}^2$$=180\times {10}^{-4}m$

Step 2: Finding weight of the person

Weight of the person$=mg$

$$\begin{gathered} =60\times 10 \\ =600N \end{gathered}$$

Step 3: Finding the pressure

We know that, pressure is defined as force per unit area.

$$\begin{gathered} Pressure=\frac{Force}{Area} \\ =\frac{600}{180\times {10}^{-4}} \\ =\frac{10}{3\times {10}^{-4}} \\ Pressure=\frac{{10}^5}{3}N{m}^{-2} \end{gathered}$$

Therefore, the pressure exerted on the ground by the person is $\frac{{10}^5}{3}N{m}^{-2}$