A person is moving in a circle of radius $r$ with constant speed $v$ .The change in velocity in moving from $A$ to $B$ is

2 v c o s 40^{\circ}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 v s i n 40^{\circ}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 v c o s 20^{\circ}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 v s i n 20^{\circ}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $2 v s i n 20^{\circ}$
$| Δ \to v | = 2 v s i n \frac{θ}{2} = 2 v s i n \frac{40^{\circ}}{2} = 2 v s i n 20^{\circ}$

Suggest Corrections

Similar questions

A particle is moving on a circular path of radius r with uniform velocity v. The change in velocity when the particle moves from P to Q is $(∠ P O Q = 40^{\circ})$

A particle is moving in a circle of radius r having centre O, with constant speed v. What is the change in velocity in moving from A to B? $(∠ A O B = 40^{\circ})$

Q. A particle is moving in a circle in a radius

r

with a constant speed

v

. The change in velocity after the particle has traveled a distance equal to

(\frac{1}{8})^{t h}

of the circumference of the circle is:

Q. Figure shows a body of mass m moving with a uniform speed v along a circle of radius r. The change in velocity in going from A to B is

Join BYJU'S Learning Program

A person is moving in a circle of radius r with constant speed v .The change in velocity in moving from A to B is

The correct option is D 2vsin20∘|Δ→v|=2vsinθ2=2vsin40∘2=2vsin20∘

A person is moving in a circle of radius $r$ with constant speed $v$ .The change in velocity in moving from $A$ to $B$ is

The correct option is D $2 v s i n 20^{\circ}$
$| Δ \to v | = 2 v s i n \frac{θ}{2} = 2 v s i n \frac{40^{\circ}}{2} = 2 v s i n 20^{\circ}$