Question

A person moves towards East for $3m$, then towards North for $4m$ and then moves vertically up by $5m$. What is his distance now from the starting point?

• A. $5\sqrt{2}m$
• B. $5m$
• C. $10m$
• D. $20m$

Answer 1

The correct option is A $5\sqrt{2}m$

Given,

Distance toward east $OA=3m$

Distance toward east $AB=4m$

Distance upward $BC=5m$

Apply Pythagoras in $\Delta OAB,OB=\sqrt{O{A}^2+A{B}^2}=\sqrt{3^2+4^2}=5m$

Apply Pythagoras in $\Delta OBCOC=\sqrt{O{B}^2+B{C}^2}=\sqrt{5^2+5^2}=5\sqrt{2}m$

The distance from starting point is $5\sqrt{2}m$