A person normally weighing 60kg stands on a platform which oscillates up and down simple harmonically with a frequency 2Hz and an amplitude 5cm.if a machine on the platform gives the person's weight,then consider the following statements :
A
The maximum reading of machine will be 108kg
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B
The maximum reading of machine will be 90kg
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C
The minimum reading of machine will be 12kg
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D
The minimum reading of the machine will be zero correct statements are:
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Solution
The correct options are A The maximum reading of machine will be 108kg C The minimum reading of machine will be 12kg Maximum a=w2A =(4π)2×0.05 =16π2×0.05 =8 mg=60⇒m=6010=6 Wmax=m(g+a) =6×(18) =108kg Wmin=6(g−a)=12kg