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Standard VIII

Physics

Normal Force

A person of 4...

Question

A person of 40 $k g$ is managing to be at rest between $3$ vertical walls by pressing one wall $A$ by his hands and feet and $B$ with his back as shown in fie The coeff of friction between his body and the wall is $0.8$ . The normal force exerted by the person is
( $g = 10 m / s^{2})$

250 N

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200 N

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100 N

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0 N

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Solution

The correct option is A $250 N$
$\begin{matrix} M a s s o f m a n = 50 k g \cdot g = 10 m / s^{2} F r i c t i o n a l f o r c e d e v e l o p e d b e t w e e n h a n d s, l e g s a n d b a c k s i d e w i t h t h e w a l l t h e w a l l t h e w e i g h t o f m a n . S o, h e r e m a i n s i n e q u i l i o b r i u m . H e g i v e s e q u a l f o r c e o n b o t h t h e w a l l s s o g e t s e q u a l r e a c t i o n R f r o m b o t h t h e w a l l s . I f h e a p p l i e s u n e q u a l f o r c e s R s h o u l d b e d i f f e r e n t h e c a n^{'} t r e s t b e t w e e n t h e w a l s s . F r i c t i o n a l f o r c e 2 μ R b a l a n c e h i s w e i g h t . f r o m t h e g i v e n f r e e b o d y d i a g r a m, μ R + μ R = 40 g \Rightarrow 2 μ R = 40 \times 10 \Rightarrow R = \frac{40 \times 10}{2 \times 0.8} = 250 N \end{matrix}$
Hence,
option $(A)$ is correct answer.

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A person of 40kg is managing to be at rest between 3 vertical walls by pressing one wall A by his hands and feet and B with his back as shown in fie The coeff of friction between his body and the wall is 0.8 . The normal force exerted by the person is(g=10m/s2)

A person of 40 $k g$ is managing to be at rest between $3$ vertical walls by pressing one wall $A$ by his hands and feet and $B$ with his back as shown in fie The coeff of friction between his body and the wall is $0.8$ . The normal force exerted by the person is
( $g = 10 m / s^{2})$