A person of mass 60kg inside a lift of mass 940kg presses the button on control panel. The lift starts moving upwards with an acceleration of 1 m/s2. If g=10m/s2 , the tension in the supporting cable is
A
660N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
10000N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
10340N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
11000N
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D11000N Mass of the person, m=60kg
Mass of lift, M=940kg, a=1m/s2, g=10m/s2
Let T be the tension in the supporting cable T−(M+m)g=(M+m)aT=(M+m)(a+g)=(940+60)(1+10)=11000N