→vrg=→vm+→vmg⇒→vrm=→vrg−→vmg=→vrg+(−→vmg)
When man is not moving he is observing actual velocity of the rain.
→vrain=vsin60o^i−vcos60o^j
=√32v^i−v2^j(ms−1) ...(i)
When the man starts running with speed 20ms−1, rain appears to fall vertically as seen by man.
Hence, the velocity of rain with respect to man.
→vr.m=→vrain−→vman ...(ii)
Let the velocity of rain with respect to man has magnitude
|→vr.m|=v′⇒−v′^j=(√32v^i−v2^j)−20^i
−v′^j=(−20+√32v)^i−v2^j ...(iii)
Comparing left side and right side terms,
−20+√32v=0⇒v=40√3(ms−1)
v′=v2=12(40√3)=20√3(ms−1)
Hence, the actual velocity of rain (from (i)),
→vrain=√32(40√3)^i−12(40√3)^j(ms−1)
=20^i−20√3^j(ms−1)
Hence, magnitude of actual velocity of rain,
|→vr|=40√2(ms−1)
And the magnitude of velocity of rain with respect to man,
|→vr.m|=20√3(ms−1)
In relative velocity, the observer observes the velocity of an object considering himself at rest.
Consider the example of a man sitting in a moving train and observes the objects outside situated on the ground.