A person standing on the floor of an elevator drops a coin. The coin touches the floor of the elevator in time t1 when the elevator is stationary and time t2 when the elevator is moving uniformly then:
A
t1=t2
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B
t1>t2
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C
t1<t2
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D
Either B or C depending upon the direction of motion of elevator.
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Solution
The correct option is Ct1=t2 As the elevator is moving at uniform speed, so it's acceleration is zero, so, no pseudo force. Thus it can not affect the motion of the coin. Thus in both cases, the coin takes the same time. i.e, t1=t2