A person throws balls into air vertically upward in regular intervals of time of one second. The next ball is thrown when the velocity of the ball thrown earlier becomes zero. The height to which the balls rise is _____
(Assume, $g = 10 m s^{- 2}$ )

5 m

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10 m

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7.5 m

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20 m

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Solution

The correct option is A $5 m$
The person throws balls into air vertically upward in regular intervals of time of one second.And next ball is thrown when the velocity of the ball thrown earlier becomes zero.
So time to reach the highest point is 1 sec. If initial velocity is u then at highest point,
$0 = u - g t$
$t = 1 s$ $g = 10 m / s^{2}$
$u = 10 m / s$
Height (H) to which ball rises ,
0= $u^{2}$ -2gH
H= $\frac{u^{2}}{2 g}$ =5m

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A person throws balls into air vertically upward in regular intervals of time of one second. The next ball is thrown when the velocity of the ball thrown earlier becomes zero. The height to which the balls rise is _____(Assume, g=10ms−2)

A person throws balls into air vertically upward in regular intervals of time of one second. The next ball is thrown when the velocity of the ball thrown earlier becomes zero. The height to which the balls rise is _____
(Assume, $g = 10 m s^{- 2}$ )