wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

A person walks at a velocity v in a straight line forming an angle α with the plane of a plane mirror. the velocity at which he approaches his image is:
1123715_1b949dbe371a4236ba864dc00be954b8.png

A
v
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
vsinα
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2vsinα
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2vcosα
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 2vcosα
  • Since it is a plane mirror vertical component of velocity have no significance.
  • The person approaches the mirror with a horizontal speed of vcosα.
  • Hence his image also move towards the mirror with same velocity vcosα in the opposite direction.
  • Velocity at which he approaches his image is ,v=vcosα(vcosα)=2vcosα

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Doppler's Effect
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon