A person walks at a velocity V in a straight line forming an angle θ with the plane of a plane mirror. Find the velocity Vrel with which he approaches his image?
A
2Vsinθ
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B
2V
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C
2Vcosθ
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D
V2sinθ
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Solution
The correct option is A2Vsinθ If V be the velocity of approach at an angle θ, then velocity along the perpendicular direction will be Vsinθ The image will also approach at the same speed, hence the relative speed of approach will be 2Vsinθ