A person wants to make a cylindrical box which is open from the top. If the height of that box is 10 cm and radius is 7 cm find the area of sheet which is required to make it

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Solution

Area of sheet required=T.S.A. of cylinder-Area of top of cylinder
$2 π r (r + h) - π r^{2}$
$2 \times \frac{22}{7}$ $\times 7$ $\times (7 + 10)$ $- \frac{22}{7}$ $\times 7$ $\times 7 = 594 c m^{2}$

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A person wants to make a cylindrical box which is open from the top. If the height of that box is 10 cm and radius is 7 cm find the area of sheet which is required to make it

Area of sheet required=T.S.A. of cylinder-Area of top of cylinder2πr(r+h)−πr22×227 ×7 ×(7+10) −227 ×7 ×7=594cm2

Area of sheet required=T.S.A. of cylinder-Area of top of cylinder
$2 π r (r + h) - π r^{2}$
$2 \times \frac{22}{7}$ $\times 7$ $\times (7 + 10)$ $- \frac{22}{7}$ $\times 7$ $\times 7 = 594 c m^{2}$