If the length, breadth and height of a cuboidal box are $75 c m, 50 c m$ and $40 c m$ . Find area of sheet required to make the box whose top is open.

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Solution

Given: Length of a cuboidal sheets $= l = 75$ cm
Breadth of a cuboidal sheets $= b = 50$ cm
Height of a cuboidal sheets $= h = 40$ cm
Area of sheets required to make the box whose top is open $=$ Total surface area of the box $- l \times b$
$= 2 (l b + b h + l h) - l b$
$= 2 (b h + l h) + l b$
$= 2 (b + l) h + l b$
$= 2 \times (50 + 75) \times 40 + 75 \times 50$ sq.cm
$= 2 \times 125 \times 40 + 3750 ‬$ sq.cm
$= 10000 + 3750 = 13750 ‬$ sq.cm

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If the length, breadth and height of a cuboidal box are 75cm,50cm and 40cm. Find area of sheet required to make the box whose top is open.

If the length, breadth and height of a cuboidal box are $75 c m, 50 c m$ and $40 c m$ . Find area of sheet required to make the box whose top is open.