A photoelectric cell is connected to a source of variable potential difference, connected across it and the photoelectric current resulting $(μ A)$ is plotted against the applied potential difference (V). The graph in the broken line represents one for a given frequency and intensity of the incident radiation. If the frequency is increased and the intensity is reduced, then which of the following graphs of unbroken line represents the new situation?

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Solution

The correct option is C D
Since the intensity is reduced to half, means the number of photon falling per unit area becomes half. So the photoelectric current will decreases .So D is correct option. But by increasing frequency stopping Potential will shift more into the negative x-axis .

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The correct option is C DSince the intensity is reduced to half, means the number of photon falling per unit area becomes half. So the photoelectric current will decreases .So D is correct option. But by increasing frequency stopping Potential will shift more into the negative x-axis .

The correct option is C D
Since the intensity is reduced to half, means the number of photon falling per unit area becomes half. So the photoelectric current will decreases .So D is correct option. But by increasing frequency stopping Potential will shift more into the negative x-axis .