Photoelectric cell is connected to a source of variable potential difference connected across it and the photoelectric current is plotted against the applied potential difference and is represented by B. If the frequency is increased and the intensity is reduced, the curve which now represents situation is:

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Solution

The correct option is C D
When the frequency will increase then the kinetic energy of the photo electron coming out of the cell will also increase so we need more potential to stop it i.e the stopping potential will also also high. But the intensity of the light was decreased which will cause a decrease in total current. So the curve D will reflects the situation.

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Q. A photoelectric cell is connected to a source of variable potential difference, connected across it and the photoelectric current resulting

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is plotted against the applied potential difference (V). The graph in the broken line represents one for a given frequency and intensity of the incident radiation. If the frequency is increased and the intensity is reduced, then which of the following graphs of unbroken line represents the new situation?

The photo-electric cell is connected to a source of variable potential difference, connected across it and the resulting photo-electric current $(μ A)$ is plotted against the applied potential difference (V). The graph in the broken line represents a case for a given frequency and intensity of the incident radiation. If the frequency is increased and the intensity is reduced, which of the following graphs of unbroken line represent the new situation?