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Question

A photographic flash unit consists of a xenon-filled tube. It gives a flash of average power 2000 W for 0.04 s. The flash is due to discharge of a fully charged capacitor of 40 μF. The voltage to which it is charged before a flash is given by the unit is

A
1500 V
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B
2000 V
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C
2500 V
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D
3000 V
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Solution

The correct option is B 2000 V
Energy due to this photographic flash is given by:
EP=P×t
EP=2000×0.04 J
Also, we know that energy stored in a fully stored capacitor is given by EC=12CV2.
Now, we know as the energy given by flashlight is due to discharge from capacitor
EP=EC
2000×0.04 = 12×40×106×V2
V2=4×106
V=2×103=2000 V
The voltage to which it is charged before a flash is produced is 2000 V

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