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Question

A photon creates a pair of electron-positron with equal kinetic energy. Let kinetic energy of each particle is 0.29 MeV. Then what should be energy of the photon

A
1.60 MeV
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B
1.63 MeV
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C
2.0 MeV
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D
1.90 MeV
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Solution

The correct option is B 1.60 MeV
The minimum energy of photon for pair production =0.51Mev
Total =2×0.51Mev=1.02
K.E of each = 0.29
TotalKE=2×0.29
Total energy of photon =1.02+0.58=1.6Mev

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