A physicist wishes to eject electrons by shining light on a metal surface- The light source emits light of wavelength of 450 nm- The table lists the only available metal and their work functions- begin matrix Metal - W - 0 eV Barium -2-5 11Lithium - 2-3 1Tantalum- 4-2 1 Tungsten- 4-5 lend matrix Which option correctly identifies the metal that will produce the most energetic electrons and their energies-A- Lithium- 0-45 eVB- Tungsten- 1-75 eVC- Lithium- 0-15 eVD- Tungsten- 2-75 eV

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Standard XII

Physics

P-N Junction

A physicist w...

Question

A physicist wishes to eject electrons by shining light on a metal surface. The light source emits light of wavelength of 450 nm. The table lists the only available metal and their work functions.
$\begin{matrix} M e t a l & W_{0} (e V) B a r i u m & 2.5 L i t h i u m & 2.3 T a n t a l u m & 4.2 T u n g s t e n & 4.5 \end{matrix}$

Which option correctly identifies the metal that will produce the most energetic electrons and their energies?

Lithium, 0.45 eV

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Tungsten, 1.75 eV

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Lithium, 0.15 eV

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Tungsten, 2.75 eV

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Solution

The correct option is A Lithium, 0.45 eV
$Δ E = W_{0} + E; (E_{K}) = Δ E - W_{0}$
For maximum value of $(E_{K}), W_{0}$ should be minimum
$W_{0}$ for lithium =2.3 eV
$∴ (E_{K}) = 2.75 - 2.3 = 0.45 e V$ .

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Q. Which option correctly identifies metal that will produce the most energetic electrons and their energies ?

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The correct option is A Lithium, 0.45 eVΔE=W0+E;(EK)=ΔE−W0 For maximum value of (EK),W0 should be minimum W0 for lithium =2.3 eV ∴(EK)=2.75−2.3=0.45eV.

The correct option is A Lithium, 0.45 eV
$Δ E = W_{0} + E; (E_{K}) = Δ E - W_{0}$
For maximum value of $(E_{K}), W_{0}$ should be minimum
$W_{0}$ for lithium =2.3 eV
$∴ (E_{K}) = 2.75 - 2.3 = 0.45 e V$ .