A physicist wishes to eject electrons by shining light on a metal surface- The light source emits light of wavelength of 450 nm- The table lists the only available metal and their work functions- begin matrix Metal - W - 0 eV Barium -2-5 11Lithium - 2-3 1Tantalum- 4-2 1 Tungsten- 4-5 lend matrix Which option correctly identifies the metal that will produce the most energetic electrons and their energies-A- Lithium- 0-45 eVB- Tungsten- 1-75 eVC- Lithium- 0-15 eVD- Tungsten- 2-75 eV

2967

You visited us 2967 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

P-N Junction

A physicist w...

Question

A physicist wishes to eject electrons by shining light on a metal surface. The light source emits light of wavelength of 450 nm. The table lists the only available metal and their work functions.
$\begin{matrix} M e t a l & W_{0} (e V) B a r i u m & 2.5 L i t h i u m & 2.3 T a n t a l u m & 4.2 T u n g s t e n & 4.5 \end{matrix}$

Which option correctly identifies the metal that will produce the most energetic electrons and their energies?

Lithium, 0.45 eV

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Tungsten, 1.75 eV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Lithium, 0.15 eV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Tungsten, 2.75 eV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A Lithium, 0.45 eV
$Δ E = W_{0} + E; (E_{K}) = Δ E - W_{0}$
For maximum value of $(E_{K}), W_{0}$ should be minimum
$W_{0}$ for lithium =2.3 eV
$∴ (E_{K}) = 2.75 - 2.3 = 0.45 e V$ .

Suggest Corrections

Similar questions

Which option correctly identifies the metal that will produce the most energetic electrons and their energies?

A physicist wishes to eject electrons by shining light on a metal surface. The light source emits light of wavelength of 450 nm. The table lists the only available metal and their work functions.

Q. A physicist wishes to eject electrons by shining light on a metal surface. The light source emits light of wavelength of 450 nm. The table lists the only available metal and their work functions.

\begin{matrix} M e t a l & W_{0} (e V) B a r i u m & 2.5 L i t h i u m & 2.3 T a n t a l u m & 4.2 T u n g s t e n & 4.5 \end{matrix}

Which metal(s) can be used to produce electrons by the photoelectric effect from given source of light?

A student performs an experiment to observe photoelectric effect by shining light on a metal surface. The light source limits light of wavelength 450nm. The table given below lists the available metals and their corresponding work functions
$\begin{matrix} M e t a l & ϕ (e v) T u n g s t e n & 4.5 L i t h i u m & 2.3 B a r i u m & 2.5 T a n t a l u m & 4.2 \end{matrix}$

Which of the above metals can be used to produce electrons by the photoelectric effect from the given source of light?

Suppose the photoelectric experiment is done separately with these metals with light of wavelength 450nm. The maximum magnitude of stopping potential amongst all the metals is

Q. Which option correctly identifies metal that will produce the most energetic electrons and their energies ?

Join BYJU'S Learning Program

The correct option is A Lithium, 0.45 eVΔE=W0+E;(EK)=ΔE−W0 For maximum value of (EK),W0 should be minimum W0 for lithium =2.3 eV ∴(EK)=2.75−2.3=0.45eV.

The correct option is A Lithium, 0.45 eV
$Δ E = W_{0} + E; (E_{K}) = Δ E - W_{0}$
For maximum value of $(E_{K}), W_{0}$ should be minimum
$W_{0}$ for lithium =2.3 eV
$∴ (E_{K}) = 2.75 - 2.3 = 0.45 e V$ .