A student performs an experiment to observe photoelectric effect by shining light on a metal surface- The light source limits light of wavelength 450 nm - The table given below lists the available metals and their corresponding work functions beginarray - WhineMetal - -phiev IIVhline Tungsten - 4-5 Illhline Lithium - 2-3 -Ilhline Barium - 2-5 lIVhlineTantalum - 4-2 illhline end array Suppose the photoelectric experiment is done separately with these metals with light of wavelength 450 nm- The maximum magnitude of stopping potential amongst all the metals isA- 2-75 VB- 0-25 VC- 4-5 VD- 0-45 V

The correct option is D 0.45 V K_max = eV_0 ⇒ V_0 = K_max/e = E_incident ϕ/e = ( 2.75 2.3/e ) = 0.45V ...

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Standard XII

Physics

Intensity in Photon Model

A student per...

Question

A student performs an experiment to observe photoelectric effect by shining light on a metal surface. The light source limits light of wavelength 450nm. The table given below lists the available metals and their corresponding work functions
$\begin{matrix} M e t a l & ϕ (e v) T u n g s t e n & 4.5 L i t h i u m & 2.3 B a r i u m & 2.5 T a n t a l u m & 4.2 \end{matrix}$

Suppose the photoelectric experiment is done separately with these metals with light of wavelength 450nm. The maximum magnitude of stopping potential amongst all the metals is

2.75 V

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4.5 V

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0.45 V

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0.25 V

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Solution

The correct option is C
0.45 V

$K_{m a x} = e V_{0}$
$\Rightarrow V_{0} = \frac{K_{m a x}}{e} = \frac{E_{i n c i d e n t} - ϕ}{e} = (\frac{2.75 - 2.3}{e}) = 0.45 V$

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A student performs an experiment to observe photoelectric effect by shining light on a metal surface. The light source limits light of wavelength 450nm. The table given below lists the available metals and their corresponding work functions
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The correct option is C 0.45 V Kmax=eV0 ⇒V0=Kmaxe=Eincident−ϕe=(2.75−2.3e)=0.45V

The correct option is C
0.45 V

$K_{m a x} = e V_{0}$
$\Rightarrow V_{0} = \frac{K_{m a x}}{e} = \frac{E_{i n c i d e n t} - ϕ}{e} = (\frac{2.75 - 2.3}{e}) = 0.45 V$