Question

Pick out the solution from the values given in the bracket next to each equation. Show that the other values do not satisfy the equation.

$5m=60(10,5,12,15)$

Answer 1

Given equation is $5m=60$.......(i)

(i) Let $m=10$ in equation(i) then L.H.S $=5\left(10\right)=50$ and
R.H.S$=60$
Therefore, L.H.S$\ne$R.H.S.
Thus, $m=10$ can't be a solution for the equation.
(ii) Let $m=5$ in equation(i) then L.HS$=5\left(5\right)=25$ and
R.H.S$=60$
Thus, L.H.S$\ne$R.H.S.
Thus, $m=5$ can't be a solution.
(iii) Similar way, for $m=12$ then L.H.S$=5\left(12\right)=60$ and
R.H.S$=60$
Thus, L.H.S$=$R.H.S.
Thus, $m=12$ is a solution for the given equation.
(iv) For $m=15$ then L.H.S$=5\left(15\right)=75$ and
R.H.S$=60$
$\therefore$L.H.S$\ne$R.H.S
Thus, $m=15$ can't be a solution.
Hence, $m=12$ is the only solution for the given equation.