A picnic spot is $55$ km away from a school. The first stop is taken at $22$ km from the school. What percentage of the distance is remaining to reach the destination?

40%

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80%

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20%

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60%

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Solution

The correct option is D 60%
Distance of the picnic spot from the school $= 55$ km
Distance travelled before taking first stop $= 22$ km

Remaining distance $= 55 - 22 = 33$ km

Therefore, percentage of distance remaining is $\frac{33}{55} \times 100 = 60 %$ .

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Q. The picnic spot is 55 km away. The first stop is taken at 22 km from the school. percentage of the distance is remaining to reach the destination.

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A picnic spot is 55 km away from a school. The first stop is taken at 22 km from the school. What percentage of the distance is remaining to reach the destination?

The correct option is D 60%Distance of the picnic spot from the school =55 km Distance travelled before taking first stop =22 km Remaining distance =55−22=33 km Therefore, percentage of distance remaining is 3355×100=60%.

A picnic spot is $55$ km away from a school. The first stop is taken at $22$ km from the school. What percentage of the distance is remaining to reach the destination?

The correct option is D 60%
Distance of the picnic spot from the school $= 55$ km
Distance travelled before taking first stop $= 22$ km

Remaining distance $= 55 - 22 = 33$ km

Therefore, percentage of distance remaining is $\frac{33}{55} \times 100 = 60 %$ .