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Question

A piece of iron weighs 44.5gf in air and 39.5gf in water. The R.D. of iron is X. Find X

A
7
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B
6
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C
9
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D
4
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Solution

The correct option is C 9
weight in air =44.5gf=0.445gN
weight in water =39.5gf=0.395gN
volume of the iron =Vi
density of the iron =d
Vi×dg=0.445g
Vi×d=0.445
density of water =1000kg/m3
Vi×1000×g=0.445g0.395g
1000V=0.05
V=0.00005
d=0.445/0.00005
DENSITY OF IRON: 8900kg/m3=8.9g/cm3

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