A solid rectangular piece of iron measures $1.05 m \times 70 c m \times 1.5 c m$ . Find the weight of this piece in kilograms, if $1 c m^{3}$ of iron weighs $8 g r a m s$ .

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Solution

REF. Image.
$v o l^{n} = 105 \times 70 \times 1.5$
$v o l^{n} = 11025 c m^{3}$
$1 c m^{3}$ weights 8 gm
$11025 c m^{3}$ weight
$11025 \times 8$
= 88200 gm
Or 88.2 kg

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A solid rectangular piece of iron measures 1.05 m×70 cm×1.5 cm. Find the weight of this piece in kilograms, if 1 cm3 of iron weighs 8 grams.

REF. Image.voln=105×70×1.5voln=11025cm31cm3 weights 8 gm11025cm3 weight 11025×8= 88200 gmOr 88.2 kg

A solid rectangular piece of iron measures $1.05 m \times 70 c m \times 1.5 c m$ . Find the weight of this piece in kilograms, if $1 c m^{3}$ of iron weighs $8 g r a m s$ .

REF. Image.
$v o l^{n} = 105 \times 70 \times 1.5$
$v o l^{n} = 11025 c m^{3}$
$1 c m^{3}$ weights 8 gm
$11025 c m^{3}$ weight
$11025 \times 8$
= 88200 gm
Or 88.2 kg