A solid rectangular piece of iron measures 1.05 m × 70 cm × 1.5 cm. Find the weight of this piece in kilograms if 1 cm³ of iron weighs 8 grams.

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Solution

$1 m = 100 c m$
∴ Dimensions of the iron piece = $105 cm \times 70 cm \times 1.5 cm$
Total volume of the piece of iron $= (105 \times 70 \times 1.5) = 11025 c m^{3}$
1 cm³ measures 8 gms.
∴Weight of the piece $= 11025 \times 8 = 88200 g = \frac{88200}{1000} = 88.2 k g (b e c a u s e 1 k g = 1000 g)$

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A solid rectangular piece of iron measures 1.05 m × 70 cm × 1.5 cm. Find the weight of this piece in kilograms if 1 cm3 of iron weighs 8 grams.

1m=100cm ∴ Dimensions of the iron piece = 105 cm×70 cm×1.5 cm Total volume of the piece of iron =(105×70×1.5)=11025 cm3 1 cm3 measures 8 gms. ∴Weight of the piece =11025 × 8 = 88200 g =882001000 = 88.2 kg because 1 kg = 1000 g

A solid rectangular piece of iron measures 1.05 m × 70 cm × 1.5 cm. Find the weight of this piece in kilograms if 1 cm³ of iron weighs 8 grams.