A piece of paper of dimensions 1-5 - - 20 -has area -

Given, dimension 1.5 𝑚 × 20 𝑐𝑚 𝐴𝑟𝑒𝑎(𝐴)=𝑙𝑒𝑛𝑔𝑡ℎ(𝑙) × 𝑏𝑟𝑒𝑎𝑑𝑡ℎ (𝑏) So, nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; 𝐴𝑟𝑒𝑎 = 1.5 𝑚 × 20 𝑐𝑚 [Since 1 𝑚=100 𝑐 ...

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Standard VIII

History

Aurangzeb

A piece of pa...

Question

A piece of paper of dimensions $1.5 m \times 20 c m$
has area :

0.3

m^{2}

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3000

m^{3}

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m^{2}

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300

c m^{2}

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Solution

The correct option is A 0.3 $m^{2}$
Given, dimension $1.5 m \times 20 c m$
$A r e a (A) = l e n g t h (l) \times b r e a d t h (b)$
So, $A r e a = 1.5 m \times 20 c m$
[Since 1 𝑚=100 𝑐𝑚]
$A r e a = 1.5 m \times 0.20 m$
$A r e a = 0.3 m^{2}$
Hence option (iii) is correct.

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A piece of paper of dimensions 1.5m×20cm has area :

The correct option is A 0.3 m2Given, dimension 1.5m×20cm Area(A)=length(l)×breadth(b) So, Area=1.5m×20cm [Since 1 𝑚=100 𝑐𝑚] Area=1.5m×0.20m Area=0.3m2 Hence option (iii) is correct.

A piece of paper of dimensions $1.5 m \times 20 c m$
has area :

The correct option is A 0.3 $m^{2}$
Given, dimension $1.5 m \times 20 c m$
$A r e a (A) = l e n g t h (l) \times b r e a d t h (b)$
So, $A r e a = 1.5 m \times 20 c m$
[Since 1 𝑚=100 𝑐𝑚]
$A r e a = 1.5 m \times 0.20 m$
$A r e a = 0.3 m^{2}$
Hence option (iii) is correct.