Question

A piece of wire $3\frac{3}{4}$ m long broke into two pieces. One piece is $1\frac{1}{2}$ m long. How long is the other piece?

Answer 1

Required length of other piece of wire = $\left(3\frac{3}{4}-1\frac{1}{2}\right)\mathrm{m}$

=$\left(\frac{15}{4}-\frac{3}{2}\right)\mathrm{m}$

=$\left(\frac{15-6}{4}\right)\mathrm{m}$ [∵ LCM of 4 and 2 = 4]

= $\frac{9}{4}\mathrm{m}=2\frac{1}{4}\mathrm{m}$

Hence, the length of the other piece of wire is $2\frac{1}{4}\mathrm{m}$.