Length of the wire = Perimeter of the equilateral triangle
= 3 Side of the equilateral triangle = (3 8.8) cm = 26.4 cm
Let the wire be bent into the form of a circle of radius r cm.
Circumference of the circle = 26.4 cm
⇒
⇒
⇒ r = cm = 4.2 cm
∴ Diameter = 2r = (2 × 4.2) cm = 8.4 cm
Hence, the diameter of the ring is 8.4 cm.