A piece of wood is 3 m long, 2 m wide, and has a thickness of 1 m. Find the density, if its mass is 2 kg.

$0.33 k g / m^{3}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$0.33 k g / c m^{3}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$3 k g / m^{3}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$3 k g / c m^{3}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
$0.33 k g / m^{3}$

Volume of the wood (cuboid) is given by the product of its dimensions.
$V = 1 \times 2 \times 3 m$
$V = 6 m^{3}$

Density of wood is given by:
$ρ = \frac{M}{V}$
where:
$M : Mass of wood$

$ρ = \frac{2 k g}{6 m^{3}}$
$ρ = 0.33 k g m^{3}$

Suggest Corrections

Similar questions

A piece of wood is $3 m$ long, $2 m$ wide and has a thickness of $1 m$ . Find the density of wood if its mass is $2 k g$ .

3 m

2 m

1 m

2 k g

3 m

2 m

1 m

2 kg

1 m \times 2 m \times 3 m

2 k g

1000 k g m^{- 3}

Join BYJU'S Learning Program