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Byju's Answer
Standard XII
Chemistry
EMF
A piece of zi...
Question
A piece of zinc metal is dipped in a
0.1
M
solution of zinc salt. The salt is dissociated to the extent of
20
%. Calculate the electrode potential of
Z
n
2
+
/
Z
n
.
(Given:
E
∘
Z
n
2
+
/
Z
n
=
−
0.76
v
o
l
t
).
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Solution
[
Z
n
2
+
]
=
0.1
×
0.2
=
0.02
M
Z
n
2
+
+
2
e
−
→
Z
n
(Reduction)
E
Z
n
2
+
/
Z
n
=
E
∘
Z
n
2
+
/
Z
n
+
0.0591
2
log
10
[
Z
n
2
+
]
.
−
0.8102
v
o
l
t
e
.
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0
Similar questions
Q.
A Zinc electrode is placed in a
0.1
M
solution at
25
o
C
. Assuming that salt is dissociated to
20
% at this dilution, calculate the electrode potential.
Given :
E
Z
n
2
+
/
Z
n
=
−
0.76
V
Q.
A zinc rod is dipped in
0.1
M
solution of
Z
n
S
O
4
. The salt is
95
%
dissociated at this dilution at
298
K
. Calculate the electrode potential.
[
E
o
Z
n
2
+
/
Z
n
=
−
0.76
V
]
.
Q.
A zinc rod is dipped in
0.1
M solution of
Z
n
S
O
4
. The salt is
95
%
dissociated at this
298
K. Calculate the electrode potential
[
E
0
Z
n
+
+
/
Z
n
=
−
0.76
e
V
]
.
Q.
A zinc electrode is placed in a 0.1M solution at
25
0
C
. assuming that the salt is 20% dissociated at this dilutions calculate the electrode reduction potential.
E
0
(
Z
n
2
+
|
Z
n
)
=
−
0.76
V
Q.
A zinc rod is placed in
0.1
M
solution of zinc sulphate
(
Z
n
S
O
4
)
at 25°C. Assuming that the salt is dissociated to the extent of 95 percent at this dilution, calculate the potential of the electrode at this temperature:
(
E
∘
Z
n
2
+
,
Z
n
=
−
0.76
V
)
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