Question

A pile of $0.50\text{m}$ diameter and of length $10\text{m}$ is embedded in a deposit of clay. The undrained strength parameters of the clay are cohesion $=60{\text{kN/m}}^2$ and the angle of internal friction $=0$. The skin friction capacity (kN) of the pile for an adhesion factor is 0.6, is

• A. 671
• B. 565
• C. 283
• D. 106

Answer 1

The correct option is B 565

Diameter of pile,
$=0.5\text{m}$
Length $=10\text{m}$
$C_u=60{\text{kN/m}}^2$
Adhesion factor,
$\alpha =0.6$
Skin friction capacity,
$=f_s.A_s$
$=\alpha C_u.(\pi D\times L)$
$=0.6\times 60\times \pi \times 0.5\times 10$
$=565.48\text{kN}$