A plane electromagnetic wave- propagating in space- has an electric field of amplitude 9- 103 V-m- The amplitude of the magnetic field is-

The speed of an electromagnetic wave is, c=E_oB_o ∴ B_o=E_oc=9× 10^33× 10^8=3× 10^ 5 T. Hence, (D) is the correct answer. ...

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Standard XII

Physics

Wave Speed expression

A plane elect...

Question

A plane electromagnetic wave, propagating in space, has an electric field of amplitude $9 \times 10^{3} V/m$ . The amplitude of the magnetic field is,

2.7 \times 10^{12} T

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9.0 \times 10^{- 3} T

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3.0 \times 10^{- 4} T

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3.0 \times 10^{- 5} T

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Solution

The correct option is D $3.0 \times 10^{- 5} T$
The speed of an electromagnetic wave is, $c = \frac{E_{o}}{B_{o}}$

$∴ B_{o} = \frac{E_{o}}{c} = \frac{9 \times 10^{3}}{3 \times 10^{8}} = 3 \times 10^{- 5} T .$

Hence, $(D)$ is the correct answer.

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A plane electromagnetic wave, propagating in space, has an electric field of amplitude 9×103 V/m. The amplitude of the magnetic field is,

The correct option is D 3.0×10−5 TThe speed of an electromagnetic wave is, c=EoBo ∴Bo=Eoc=9×1033×108=3×10−5 T. Hence, (D) is the correct answer.

A plane electromagnetic wave, propagating in space, has an electric field of amplitude $9 \times 10^{3} V/m$ . The amplitude of the magnetic field is,

The correct option is D $3.0 \times 10^{- 5} T$
The speed of an electromagnetic wave is, $c = \frac{E_{o}}{B_{o}}$

$∴ B_{o} = \frac{E_{o}}{c} = \frac{9 \times 10^{3}}{3 \times 10^{8}} = 3 \times 10^{- 5} T .$

Hence, $(D)$ is the correct answer.