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Question

A plane mirrior is inclined to horizontal at 60. A ray of light is incident on the mirror at an angle of incidence 30 as shown. Angel which the reflected ray makes with horizontal is

A
30
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B
60
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C
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D
45
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Solution

The correct option is C 0 angle of incidence = angle of reflection ∠AOC=∠BOC∠BOC=30∘Now, ∠POC=90 (normal line)∴△BOC+∠BOP=90⇒30∘+∠BOP=90∘∴∠BOP=60∘but ∠OPB=60∘So ∠OPB=∠BOP=60∘these are alternate angle pair of lineOB and PQHence, OB//PB.SO, reflected ray makes 0∘ with horizontalHence, (C) is correct option.

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