Question

# A planet in a distant solar system is 10 times more massive than the earth and its radius is 10 times smaller. Given that the escape velocity from the earth is 11kms−1, the escape velocity (in km s−1) from the surface of the planet would be

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Solution

## Mass of planet, MP=10Me, where Me is mass of earth. Radius of planet, RP=Re10, Where Re is radius of earth. Escape speed is given by, vP=√2GMR For planet, vP=√2G×MPRP vP=10×ve vP=10×11=110 km s−1

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