Question

A planet is observed by an astronomical refracting telescope having an objective of focal length 16 m and eye piece of focal length 20 cm. Then,

• A. The distance between objective and eyepiece is 16.02 m
• B. The angular magnification of the planet is 80
• C. The image of the planet is inverted
• D. Both A and B are correct

Answer 1

Answer: (D)

Both A and B are correct

Given: $f_0=16m$
$f_e=20cm$
$L=f_0+f_e$
$=16+0.2$
$=16.2m$
$m=\frac{f_0}{f_e}$
$=\frac{16}{0.2}$
$=80$