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Question

A planet revolves is an elliptical orbit around the sun. The semi-major and semi-minor axes are a and b, then the time period is given by.

A
T2b3
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B
T2[a+b2]3
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C
T2a3
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D
T2[ab2]3
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Solution

The correct option is C T2a3
Using Kepler's 2nd law, A=L2mT where A=πab
Also, b2=a2(1e2)
Now, at aphelion θ=0 thus a(1e)=L2GMm2(1+e)
L2m2=a(1e2)GM
Thus, from L24m2=π2a2b2T2T2a3

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