A plastic bag contains $12$ red marbles, $15$ green marbles and $5$ yellow marbles. Find the number of additional red marbles that must be added to the bag, so that the probability of randomly drawing a red marble is $\frac{3}{5}$ ?

13

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18

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28

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32

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Solution

The correct option is C $18$
Let ' $x$ ' number of additional red marbles be added to the bag.
Then, the required probability will be $\frac{12 + x}{32 + x} = \frac{3}{5}$
$\Rightarrow 60 + 5 x = 96 + 3 x$
$\Rightarrow 2 x = 36$
$\Rightarrow x = 18$
Hence, the required number of marbles is $18$ .

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A plastic bag contains 12 red marbles, 15 green marbles and 5 yellow marbles. Find the number of additional red marbles that must be added to the bag, so that the probability of randomly drawing a red marble is 35?

The correct option is C 18Let 'x' number of additional red marbles be added to the bag. Then, the required probability will be 12+x32+x=35 ⇒60+5x=96+3x ⇒2x=36 ⇒x=18Hence, the required number of marbles is 18.

A plastic bag contains $12$ red marbles, $15$ green marbles and $5$ yellow marbles. Find the number of additional red marbles that must be added to the bag, so that the probability of randomly drawing a red marble is $\frac{3}{5}$ ?

The correct option is C $18$
Let ' $x$ ' number of additional red marbles be added to the bag.
Then, the required probability will be $\frac{12 + x}{32 + x} = \frac{3}{5}$
$\Rightarrow 60 + 5 x = 96 + 3 x$
$\Rightarrow 2 x = 36$
$\Rightarrow x = 18$
Hence, the required number of marbles is $18$ .