Question

A platinum resistance thermometer reads $0^{\circ }$ when its resistance is 80 $\Omega$ and ${100}^{\circ }$ when its resistance is 90 $\Omega$. Find the temperature at the platinum scale at which the resistance is 86 $\Omega$

Answer 1

$R_1=86\Omega ,R_0=80\Omega R_{100}=90\Omega$

$t=\frac{R_1-R_0}{R_{100}-R_0}\times 100$

$=\frac{86-80}{90-80}\times 100$

$=\frac{6}{10}\times 100={60}^{\circ }C$