Question

A play ground in the form of a rectangle having semi circles on the shorter sides. Find the area when the length of the rectangular portion is $80m$ and the breadth is $42m$.

Answer 1

Area of given figure $=$ Area of rectangle $+2\times$ Area of semicircle

$AC$ is the shortest length of rectangle and diameter of semicircle.

Since,
$AC=2r42=2rr=21m\text{Area}=80\times 42+2\times \frac{1}{2}\times \frac{22}{7}\times 21\times 21=3360+1386\text{Area}=4746m^2$

Hence, this is the answer.