A window is in the form of a semi-circle with rectangle on its diameter. Find the perimeter if The length and breadth of rectangle are $20, 14 c m$

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Solution

The radius of circle is $7 c m$
The circumference of semicircle is $π r \frac{22}{7} \times 7 = 22 c m$
The outer perimeter of rectangle is $20 + 20 + 14 = 54 c m$
So total perimeter is $22 + 54 = 76 c m$

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A window is in the form of a semi-circle with rectangle on its diameter. Find the perimeter if The length and breadth of rectangle are 20,14cm

The radius of circle is 7cmThe circumference of semicircle is πr227×7=22cmThe outer perimeter of rectangle is 20+20+14=54cmSo total perimeter is 22+54=76cm

A window is in the form of a semi-circle with rectangle on its diameter. Find the perimeter if The length and breadth of rectangle are $20, 14 c m$

The radius of circle is $7 c m$
The circumference of semicircle is $π r \frac{22}{7} \times 7 = 22 c m$
The outer perimeter of rectangle is $20 + 20 + 14 = 54 c m$
So total perimeter is $22 + 54 = 76 c m$